Posted by **josh** on Thursday, June 10, 2010 at 2:14pm.

find the frictional force exerted on a 20kg block pulled slowly over a horizontal floor using a rope which makes a 30 degree angle over the horizontal. the pulling force is 100N???

i found the Fn to be 146 N what do i do from there?

- college physics -
**drwls**, Thursday, June 10, 2010 at 2:34pm
You want the frictional force, not the normal force.

100* cos 30 = 86.6 N

is the frictional force, since it is being pulled slowly and presumably not acclerating. You don't need to use the mass information to get that.

The normal force is

M g - 100N sin 30 = 146 N; you were right about that.

The coefficient of sliding friction is 86.6/146 = 0.59

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