Posted by josh on Thursday, June 10, 2010 at 2:14pm.
find the frictional force exerted on a 20kg block pulled slowly over a horizontal floor using a rope which makes a 30 degree angle over the horizontal. the pulling force is 100N???
i found the Fn to be 146 N what do i do from there?

college physics  drwls, Thursday, June 10, 2010 at 2:34pm
You want the frictional force, not the normal force.
100* cos 30 = 86.6 N
is the frictional force, since it is being pulled slowly and presumably not acclerating. You don't need to use the mass information to get that.
The normal force is
M g  100N sin 30 = 146 N; you were right about that.
The coefficient of sliding friction is 86.6/146 = 0.59
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