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A solution is 36% silver nitrate (AgNO3) by mass. The density of this solution is 1.44
g/mL. The formula weight of AgNO3 is 170
g/mol. Calculate the molality of AgNO3 in
this solution.

  • Cemistry - ,

    36% AgNO3 means 36 g AgNO3/100 g solution.
    36 g = 36/170 moles = ??
    100 g solution = volume x density. Calculate volume. Then M = moles/L soln.

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