Homework Help: Cemistry

Posted by Swagato on Wednesday, June 9, 2010 at 10:07pm.

A solution is 36% silver nitrate (AgNO3) by mass. The density of this solution is 1.44
g/mL. The formula weight of AgNO3 is 170
g/mol. Calculate the molality of AgNO3 in
this solution.

Cemistry - DrBob222, Wednesday, June 9, 2010 at 10:19pm
36% AgNO3 means 36 g AgNO3/100 g solution.
36 g = 36/170 moles = ??
100 g solution = volume x density. Calculate volume. Then M = moles/L soln.

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