MATH!
posted by Sara! .
plz how do you solve these? i keep getting the wrong answer
1. 3z/2  17/3 = 2z/3  3/2
2. 2/5b  1/4b =3
3. 23  6g = 19
please show me step by step how you do these

1. Make the denominators alike.
3z/2  17/3 = 2z/3  3/2
9z/2  34/6 = 4z/6  9/6
Add 34/6 to both sides of the equal sign. The 34/6 and the +34/6 will cancel out on the left. The +34/6 is added to 9/6
9z/6 = 4z/6 + 25/6
Subtract 4z/6 from both sides. It will cancel out on the right side. And it will be subtracted from 9z/6 on the left.
5z/6 = 25/6
Then divide 5/6 from 5z/6 and 25/6, You'll have to multiply the reciprocal of 5/6, which is 6/5.
z= 25/6 * 6/5
z= 150/30 = 5
z= 5 
2. Make the denominators alike.
2/5b  1/4b =3
8/20b  5/20b = 3
Then subtract 8/20b and 5/20b.
3/20b = 3
Then multiply 20b by both sides. It will cancel out on the left side, leaving 3 alone.
3=3(20b)
3=60b
Divide 60 by 60b and 3.
b= 3/60 < 1/20 (Simplified) 
how do you solve # 2

oh i mean # 3

Subtract 23 from both sides. It will cancel out with the +23 on the left.
23  6g = 19
6g= 4
Divide 6 from 6g and 4.
g= 4/6 < g= 2/3 
# 2 is 20

No the answer to #2 is 1/20 or .05
If it was 20 then the answer would be 3, it'd be 0.0075 
it is 3!

I always get rid of all my fractions.
#1 look at the denominators, their LCD is 6 , so multiply each term by 6 to get
9z  34 = 4z  9
5z = 25
z = 5
#2.
2/5b  1/4b =3
multiply each term by the LCD, which is 20 to get
8b  5b = 60
3b = 60
b = 20