# MATH!

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plz how do you solve these?- i keep getting the wrong answer

1. 3z/2 - 17/3 = 2z/3 - 3/2

2. 2/5b - 1/4b =3

3. 23 - 6g = 19

please show me step by step how you do these

• MATH! -

1. Make the denominators alike.
3z/2 - 17/3 = 2z/3 - 3/2
9z/2 - 34/6 = 4z/6 - 9/6

Add 34/6 to both sides of the equal sign. The -34/6 and the +34/6 will cancel out on the left. The +34/6 is added to -9/6

9z/6 = 4z/6 + 25/6

Subtract 4z/6 from both sides. It will cancel out on the right side. And it will be subtracted from 9z/6 on the left.

5z/6 = 25/6

Then divide 5/6 from 5z/6 and 25/6, You'll have to multiply the reciprocal of 5/6, which is 6/5.

z= 25/6 * 6/5
z= 150/30 = 5
z= 5

• MATH! -

2. Make the denominators alike.

2/5b - 1/4b =3
8/20b - 5/20b = 3
Then subtract 8/20b and 5/20b.

3/20b = 3

Then multiply 20b by both sides. It will cancel out on the left side, leaving 3 alone.

3=3(20b)
3=60b

Divide 60 by 60b and 3.

b= 3/60 <-- 1/20 (Simplified)

• MATH! -

how do you solve # 2

• MATH! -

oh i mean # 3

• MATH! -

Subtract 23 from both sides. It will cancel out with the +23 on the left.
23 - 6g = 19
-6g= -4

Divide -6 from -6g and -4.

g= -4/-6 <--- g= 2/3

• MATH! -

# 2 is 20

• MATH! -

No the answer to #2 is 1/20 or .05
If it was 20 then the answer would be 3, it'd be 0.0075

• MATH! -

it is 3!

• MATH! -

I always get rid of all my fractions.

#1 look at the denominators, their LCD is 6 , so multiply each term by 6 to get
9z - 34 = 4z - 9
5z = 25
z = 5

#2.
2/5b - 1/4b =3
multiply each term by the LCD, which is 20 to get
8b - 5b = 60
3b = 60
b = 20

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