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MATH!

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plz how do you solve these?- i keep getting the wrong answer


1. 3z/2 - 17/3 = 2z/3 - 3/2

2. 2/5b - 1/4b =3

3. 23 - 6g = 19

please show me step by step how you do these

  • MATH! -

    1. Make the denominators alike.
    3z/2 - 17/3 = 2z/3 - 3/2
    9z/2 - 34/6 = 4z/6 - 9/6

    Add 34/6 to both sides of the equal sign. The -34/6 and the +34/6 will cancel out on the left. The +34/6 is added to -9/6

    9z/6 = 4z/6 + 25/6

    Subtract 4z/6 from both sides. It will cancel out on the right side. And it will be subtracted from 9z/6 on the left.

    5z/6 = 25/6

    Then divide 5/6 from 5z/6 and 25/6, You'll have to multiply the reciprocal of 5/6, which is 6/5.

    z= 25/6 * 6/5
    z= 150/30 = 5
    z= 5

  • MATH! -

    2. Make the denominators alike.

    2/5b - 1/4b =3
    8/20b - 5/20b = 3
    Then subtract 8/20b and 5/20b.

    3/20b = 3

    Then multiply 20b by both sides. It will cancel out on the left side, leaving 3 alone.

    3=3(20b)
    3=60b

    Divide 60 by 60b and 3.

    b= 3/60 <-- 1/20 (Simplified)

  • MATH! -

    how do you solve # 2

  • MATH! -

    oh i mean # 3

  • MATH! -

    Subtract 23 from both sides. It will cancel out with the +23 on the left.
    23 - 6g = 19
    -6g= -4

    Divide -6 from -6g and -4.

    g= -4/-6 <--- g= 2/3

  • MATH! -

    # 2 is 20

  • MATH! -

    No the answer to #2 is 1/20 or .05
    If it was 20 then the answer would be 3, it'd be 0.0075

  • MATH! -

    it is 3!

  • MATH! -

    I always get rid of all my fractions.

    #1 look at the denominators, their LCD is 6 , so multiply each term by 6 to get
    9z - 34 = 4z - 9
    5z = 25
    z = 5

    #2.
    2/5b - 1/4b =3
    multiply each term by the LCD, which is 20 to get
    8b - 5b = 60
    3b = 60
    b = 20

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