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November 27, 2014

November 27, 2014

Posted by **kelly** on Wednesday, June 9, 2010 at 7:04pm.

- trig -
**Reiny**, Wednesday, June 9, 2010 at 8:06pmif the cotØ < 0 then tanØ < 0

then Ø is in either II or IV

and since the cosØ = √2/2 (positive)

Ø is in I or IV

so Ø is in IV

the angle in standard position is 45°

(since cos45° = √2/2)

you should know the trig ratios of the 45° by heart.

so

sinØ = -√2/2

cscØ = -2/√2

cosØ = √2/2 --- the given value

secØ = 2/√2

tanØ = -1

cotØ = -1

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