Posted by kelly on Wednesday, June 9, 2010 at 7:04pm.
if the cotØ < 0 then tanØ < 0
then Ø is in either II or IV
and since the cosØ = √2/2 (positive)
Ø is in I or IV
so Ø is in IV
the angle in standard position is 45°
(since cos45° = √2/2)
you should know the trig ratios of the 45° by heart.
so
sinØ = -√2/2
cscØ = -2/√2
cosØ = √2/2 --- the given value
secØ = 2/√2
tanØ = -1
cotØ = -1
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