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March 1, 2015

March 1, 2015

Posted by **kelly** on Wednesday, June 9, 2010 at 7:02pm.

- trig -
**Henry**, Wednesday, June 16, 2010 at 5:53pmGiven:CosA=SQRT2/2

Since the cosine is positive and the

tangent and cotangent are negative

(less than 0), we are in the 4th Quad-

rant. CosA=sqrt2/2=x/r, x=sqrt2, r=2,

Y=sqrt(r^2-x^2)=sqrt(4-2)=+/-sqrt2,

Y=-sqrt2(4th Quadrant).

SinA=y/r=-sqrt2/2.

CosA=sqrt2/2=x/r(Given)

TanA=y/x=-sqrt2/sqrt2=-1

cscA=-(2/sqrt2).

secA=2/sqrt2

CotanA=sqrt2/-sqrt2=-1

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