Posted by kelly on Wednesday, June 9, 2010 at 7:02pm.
Given:CosA=SQRT2/2
Since the cosine is positive and the
tangent and cotangent are negative
(less than 0), we are in the 4th Quad-
rant. CosA=sqrt2/2=x/r, x=sqrt2, r=2,
Y=sqrt(r^2-x^2)=sqrt(4-2)=+/-sqrt2,
Y=-sqrt2(4th Quadrant).
SinA=y/r=-sqrt2/2.
CosA=sqrt2/2=x/r(Given)
TanA=y/x=-sqrt2/sqrt2=-1
cscA=-(2/sqrt2).
secA=2/sqrt2
CotanA=sqrt2/-sqrt2=-1
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