consider 2 sample of nitrogen gas. sample 1 contains 1.5 mol of N2 and has a volume of 36.7L at 25C and 1 atm. sample 2 has a volume of 16.5L at 25C and 1 atm. calculate the number of moles of N2 in sample 2

do i use the pv= nrt equation? and do i only use the information given for sample 2 since you are finding moles in sample 2?
so you can ignore the info. for sample 1?

You can do this two ways.

One way is to use PV = nRT and, as you say, ignore sample 1.
(1 atm)(16.7 L) = n*0.08206*298 and solve for n, number of moles.
OR you can forget the PV = nRT and use the information from the two gases. I suspect the problem is trying to illustrate Avogadro's Law that equal volumes of gases at the same P and T contain equal number of molecules.
So if 1.5 mol are in the 36.7 L sample and we want to know moles in the 16.5 L sample, we can use the ratio
1.5 mol x (16.5/36.7) = ??
You should get the same answer either way.

Yes, you can use the ideal gas law equation PV = nRT to calculate the number of moles of nitrogen gas in sample 2. Since you are specifically trying to find the number of moles in sample 2, you can ignore the information given for sample 1.

To solve for the number of moles (n) in sample 2, you will need to rearrange the ideal gas law equation to solve for n:

n = PV / RT

Given:
P = 1 atm
V = 16.5 L
R = ideal gas constant = 0.0821 L·atm/mol·K (if pressure is given in atm)
T = 25°C = 298.15 K

Now you can substitute the given values into the equation to find the number of moles in sample 2:

n = (1 atm) × (16.5 L) / (0.0821 L·atm/mol·K) × (298.15 K)

By performing this calculation, you will get the number of moles of nitrogen gas in sample 2.

Yes, you are correct. To calculate the number of moles of N2 in sample 2, you can use the ideal gas law equation, which is PV = nRT. In this case, since you are only interested in sample 2, you can ignore the information given for sample 1.

The ideal gas law equation relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas. In this case, you know the volume (V2) of sample 2, its temperature (T2), and the pressure (P2) which is given as 1 atm.

The given values for sample 2 are:
Volume (V2) = 16.5 L
Temperature (T2) = 25°C = 25 + 273.15 K (converting to Kelvin)
Pressure (P2) = 1 atm

Now, rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT

Substitute the given values into the equation:
n2 = (P2 * V2) / (R * T2)

Where R is the ideal gas constant, which has a value of 0.0821 L·atm/(mol·K).

Now, plug in the values:
n2 = (1 atm * 16.5 L) / (0.0821 L·atm/(mol·K) * (25 + 273.15) K)

Calculate the right side of the equation:
n2 ≈ 0.0697706 mol

Therefore, the number of moles of N2 in sample 2 is approximately 0.0697706 mol.