Posted by Charlezetta on Tuesday, June 8, 2010 at 5:39pm.
The above formatting is not the way I wanted, so I'll repost
(x - 3/ 2)^3 .(1 / x - 3)^2
x^2 - 9/x + 2 .x^2 - 4/ x - 3
x^2 + 5x+4/(x+3)^2 * x+1/ x^2-9
It helps to use common notation and clarify using parentheses, brackets and use of spaces. "*" = multiply and "/" indicates divide online.
(x - 3/ 2)^3 .(1 / x - 3)^2 = (x - 3/ 2)^3 * (1/x - 3)^2 (?)
x^2 - 9/x + 2 .x^2 - 4/ x - 3 = (x^2 - 9/x + 2) * (x^2 - 4/x - 3) (?)
x^2 + 5x+4/(x+3)^2 * x+1/ x^2-9 = [(x^2 + 5x+4)/(x+3)^2] / (x+1)/(x^2-9) (?)
Can you improve the formatting again?
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