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November 28, 2014

November 28, 2014

Posted by **Amal** on Tuesday, June 8, 2010 at 4:08pm.

and at 10 A.M. He will be 55+ x ahead. Please help me. My brain feels foggy.

- algebra -
**Reiny**, Tuesday, June 8, 2010 at 5:11pmThere is no unique solution to your problem.

Let the time spent driving by man1 be 1 hours

then the time for man2 when he overtook man1 is t-1 hours.

let the speed of man2 be x mph

distance driven by man1 = 50t miles

distance driven by man2 = x(t-1) miles

but at the overtake, the both went the same distance, so

x(t-1) = 50t

xt - x = 50t

xt-50t = x

t(x-50) = x

t = x/(x-5) , clearly x > 50

let x = 60, then

t = 60/10 = 6 hours

check: when t = 6 hours,

distance of man 1 = 300 miles

time for second man = 5 hours, speed of second man = 60 mph, distance = 300

try x=70 , so t = 3.5

distance of man1 = 3.5x50 = 175 miles

time for second man = 2.5, speed of second man = 70

distance of second man = 2.5x70 = 175

notice both combination of answers work, as will as many others as you want.

- algebra -
**Amal**, Tuesday, June 8, 2010 at 5:49pmWe know man 1 drives 50 miles per hour

man 2 goes 55 mph

- algebra -
**Amal**, Wednesday, June 9, 2010 at 11:32amThe answer differs from yours.

- algebra -
**Amal**, Tuesday, June 15, 2010 at 6:08pmPlease help! I'm still waiting!

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