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July 30, 2014

July 30, 2014

Posted by **Jenny** on Tuesday, June 8, 2010 at 3:15pm.

Thank you for helping me!

- trig -
**Henry**, Wednesday, June 16, 2010 at 7:10pmGiven: X=2Y^2+3

Vertex form:X=(y-k)^2+h, h and k are the x and y-coordinates of the vertex.

X=2(y-0)^2+3, V(h,k)=(3,0), Directrix:

X=h-1/4a=3-1/8=2 7/8,Y=K=0, D(2 7/8,0).

Focal: X=h+1/4a=3+1/8=3 1/8, Y=k=0,

F(3 1/8,0). Axis: Y=0 (A horizontal line on the X-axis).

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