Posted by **gabriel** on Tuesday, June 8, 2010 at 8:42am.

which quadratic formula would be used to solve the following quadratic equation?

4x^2 - 5x = -2

can you show me the correct answer and how do it please

- algebra -
**MathMate**, Tuesday, June 8, 2010 at 10:00am
I would use the standard quadratic formula for ax²+bx+c=0, and

x=(-b±√(b²-4ac))/2a

Here

4x^2 - 5x = -2

can be rewritten as

4x^2 - 5x + 2 =0, so

a=4,

b=-5

c=2

substituting in the quadratic formula,

x=(-(-5)±√((-5)²-4(4)(2)))/(2*4)

which when simplified, gives

x=(5±(√7)i)/8 where i=√(-1) (complex root).

Complex numbers is a little beyond high school, but the procedure is the same.

If you are not expecting complex roots, you may want to recheck if the question you posted was correct. If not, repeat the exercise using the correct question.

- algebra -
**Rose**, Thursday, May 10, 2012 at 9:23pm
using the quadratic formula, how do you solve 2p^2 + 16p = -2p^2 + 3?

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