Posted by **bart** on Tuesday, June 8, 2010 at 12:10am.

Find the equation of a line that passes through the point (1,2)

and has a slope of 1/3. Show how you found the equation.

Would the equation be:

y-2=1/3(x-1)

Do I need to finish this? I am not sure how.

- Algebra: please check -
**troy**, Tuesday, June 8, 2010 at 12:49am
You set it up right. Don't forget your plugging in for x and y and you need to finish this.

So your equation would be

-2=1/3(1)+b

B would be your unknown y-intercept.

But this is not in slope-intercept form

So now you need to solve for b.

-2=1/3(1)+b

-2=1/3+b

subtract 1/3 from both sides you get

-2 1/3=b

or

-7/3=b

your equation would then be

y=1/3x-2 1/3

or

y=1/3x-7/3

- Algebra: please check -
**Reiny**, Tuesday, June 8, 2010 at 6:31am
There are several ways to write the equation of a straight line.

The way troy showed you is the y-intercept-slope form.

Your starting equation suggests that you have learned the point-slope form

continue from

y-2=1/3(x-1) by multiplying both sides by 3 to avoid fractions ...

3y - 6 = x-1

take everybody to the left side

-x + 3y - 5 = 0

usually we start with a positive x

x - 3y + 5 = 0

This is the general form of the equation of a straight line, and it contains no fractions.

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