Posted by **Sheila** on Monday, June 7, 2010 at 11:15pm.

The length of a rectangular field is 7 meters more than twice its width. If the perimeter is 140 meters, find the dimensions of the field.

- algebra -
**Jen**, Monday, June 7, 2010 at 11:27pm
31.5 and 38.5

- algebra -
**Jen**, Monday, June 7, 2010 at 11:27pm
Oh wait, I read it wrong, sorry.

- algebra -
**Reiny**, Monday, June 7, 2010 at 11:28pm
width --- x

length -- x+7

2(x + x+7) = 140

easy to solve...

- algebra -
**Reiny**, Monday, June 7, 2010 at 11:29pm
and I read it wrong as well, lol

width --- x

length -- 2x+7

2(x + 2x+7) = 140

easy to solve...

- algebra -
**chooey**, Monday, June 7, 2010 at 11:37pm
P=2(l+w)

width=w

length=2w+7

(w)+(w)+(2w+7)+(2w+7)=140

6w+14=140

6w=140-14

6w=126

w=126/6

w=21(width)

l=2w+7

2*21=42+7=49 (length)

- algebra -
**chooey**, Monday, June 7, 2010 at 11:39pm
I am 100% sure that my answer is right!!

By the way,in what grade is the person who asked this question (just wondering...)

- algebra -
**sachin**, Sunday, April 24, 2011 at 8:06pm
width= x

lengtth=x+2

so

x(x+2)=170

easy to solve....................

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