A student completes a titration by adding 12.0 milliliters of NaOH(aq) of unknown concentration to 16.0 milliliters of 0.15 M HCl(aq). What is the molar concentration of the NaOH(aq)?
.2M of NaOH(aq)
To find the molar concentration of NaOH(aq), we can use the concept of stoichiometry and the balanced equation for the reaction between NaOH and HCl. The balanced equation is:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
From the balanced equation, we can see that the ratio of NaOH to HCl is 1:1. This means that for each mole of NaOH, there is an equal number of moles of HCl.
Given that the volume of HCl(aq) is 16.0 milliliters and its concentration is 0.15 M, we can find the moles of HCl:
moles of HCl = volume (in liters) x concentration
= 0.016 L x 0.15 M
= 0.0024 moles
Since the ratio of NaOH to HCl is 1:1, the moles of NaOH will also be 0.0024 moles.
Now we can find the molar concentration of NaOH(aq) by dividing the moles of NaOH by the volume of NaOH added:
molar concentration of NaOH(aq) = moles of NaOH / volume of NaOH (in liters)
= 0.0024 moles / 0.012 L
= 0.20 M
Therefore, the molar concentration of NaOH(aq) is 0.20 M.
To determine the molar concentration of NaOH(aq), we can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and HCl. The balanced equation is as follows:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
First, we need to determine the number of moles of HCl that reacted with NaOH. This can be done using the molarity (M) and volume (V) information given for HCl. The equation used is:
moles of HCl = Molarity of HCl × Volume of HCl
moles of HCl = 0.15 M × 16.0 mL
Next, we need to determine the number of moles of NaOH that reacted with HCl. According to the balanced equation, the stoichiometric ratio between NaOH and HCl is 1:1. Therefore, the number of moles of NaOH is equal to the number of moles of HCl. Thus:
moles of NaOH = moles of HCl
Now, we can calculate the molar concentration of NaOH using the information provided for the volume of NaOH. The equation used is:
Molarity of NaOH = moles of NaOH / Volume of NaOH
Molarity of NaOH = moles of HCl / Volume of NaOH
Since we were not given the volume of NaOH, we cannot directly calculate the molar concentration from the information provided in the question. However, if we assume that all the NaOH reacted with the HCl, we can use the given volume of NaOH as the total volume of the NaOH(aq) solution.
Therefore:
Molarity of NaOH = moles of HCl / Volume of NaOH
Molarity of NaOH = 0.15 M × 16.0 mL / 12.0 mL
Molarity of NaOH ≈ 0.20 M
Thus, assuming that all the NaOH reacted with the HCl, the molar concentration of the NaOH(aq) solution is approximately 0.20 M.