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one positive integer is 3 less than twice another.The sum of their squares is 482.Find the integers?

  • math -

    Let one integer be x
    then the other is 2x-3

    x^2 + (2x-3)^2 = 482

    expand and solve as a quadratic.

    Hint: it actually factors, one is (5x+43) which of course would yield a non-integer solution.
    So the solution must come from the other factor.

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