200. g of a nonelectrolyte is dissolved in 1.00 kg of water. the boiling point of the solution is then measured to be 101.5 degrees C. What is the molar mass of the compound? The Kb for water is 0.51 degrees Celsius/m

To find the molar mass of the compound, we can use the concept of boiling point elevation. Boiling point elevation occurs when a solute is added to a solvent, causing the boiling point of the solution to increase compared to the pure solvent.

The formula to calculate the boiling point elevation is:

ΔTb = Kb * m * i

Where:
ΔTb = change in boiling point
Kb = molal boiling point elevation constant (given as 0.51 degrees Celsius/m)
m = molality of the solution
i = van 't Hoff factor (the number of particles the solute dissociates into when dissolved)

In this case, since the solute is a nonelectrolyte, it does not dissociate into ions, so i = 1.

First, we need to calculate the molality (m) of the solution using the given mass of the solute and the mass of the solvent:

mass of solute = 200 g
mass of solvent = 1.00 kg = 1000 g

m = moles of solute / mass of solvent

To find the moles of solute, we divide the mass of the solute by its molar mass (M):

moles of solute = mass of solute / molar mass

Now we have all the information we need to calculate the molality:

m = (mass of solute / molar mass) / mass of solvent

Next, we can substitute the calculated molality into the boiling point elevation equation to find the change in boiling point (ΔTb):

ΔTb = Kb * m * i

We already know the change in boiling point (ΔTb) is 101.5 degrees Celsius, so we can rearrange the equation to find the molal mass (M) of the solute:

M = (mass of solute / ΔTb) / (Kb * m * i)

By substituting the known values, we can solve for the molar mass (M) of the compound.

see above.