Posted by **Dave** on Sunday, June 6, 2010 at 8:58pm.

How do you find the vertical and horizontal assymptotes of the graph of the rational function?

f(x)= 3x^2-5x+2/6x^2-5x+1

f(x)= 2x+3/(ãx^2-2x+3)

- Math:use parentheses -
**MathMate**, Sunday, June 6, 2010 at 10:04pm
Vertical asymptotes in rational functions usually come from the denominator approaching zero.

In

f(x)= (3x^2-5x+2)/(6x^2-5x+1)

the denominator can be factorized as:

(3x-1)(2x-1)

at x=1/3 or x=1/2, the denominator becomes zero, and hence a vertical asymptote. You also need to check if the numerator vanishes at the same points, in which case the point will be undefined.

To find the horizontal asymptotes, do a long division, and the resulting leading constant (1/2) is the horizontal asymptote. Take care to determine from which side of y=1/2 the curve approaches the asymptote as x approaches ±∞.

## Answer This Question

## Related Questions

- Gr.11 - Rational functions graphing. - 1. Identify a rational function whose ...
- ****college algebra…radical functions**** - Create a rational function such that...
- Algebra - Graph the rational function x/(x-6) To graph the function, draw the ...
- math (calculus) PLZZZ help! - Consider the function below. (Round the answers to...
- College Algebra - 1.Use completing the square to describe the graph of the ...
- College Algebra HELP - Use the seven step method described in the book to graph ...
- Math - Create a rational function with a linear binomial in both the numerator ...
- graph from asymptotes - Is it possible to roughly sketch a graph(without ...
- Math - Verify these answers :] Would be thankies~ 1. Determine the intervals in ...
- precalculus - How do I find the vertical/horizontal compression/stretch? For the...

More Related Questions