I need some help solving for x...

It says to slove
7x+x(x-1)=0
It also asks for the x intercept

7x+x2 -x=0

6x + x2 = 0
x (6+x)=0

dividing x on both side.
x (6+x)/x=0/x
6+x= 0
x= -6

:)

From

x (6+x)=0
we get x=0, or (6+x)=0, therefore
x=0, or x=-6
These are the x-intercepts.

Thank you both for your help!!!

To solve the equation 7x + x(x-1) = 0, we need to simplify and rearrange the equation to get x on one side.

Start by distributing x to the terms inside the parentheses:
7x + x^2 - x = 0.

Combine the x terms on the left side:
x^2 + 6x = 0.

To find the x-intercepts, we need to factor out common terms. In this equation, we can factor out an x:
x(x + 6) = 0.

Now we have two possibilities that can make the equation true: either x = 0 or x + 6 = 0.

For x = 0, it is a valid solution that satisfies the equation.

For x + 6 = 0, subtract 6 from both sides to isolate x:
x = -6.

So the solutions for x are x = 0 and x = -6.

To find the x-intercepts, we set y = 0 and solve for x. The x-intercepts are the points where the graph crosses or touches the x-axis. In other words, they are the solutions to the equation when y (or f(x)) is equal to zero.

In this case, the x-intercepts can be found by setting the equation equal to zero:
7x + x(x-1) = 0.

We have already solved this equation for x above, and the solutions are x = 0 and x = -6.

Therefore, the x-intercepts of the equation 7x + x(x-1) = 0 are x = 0 and x = -6.