Posted by Anonymous on Sunday, June 6, 2010 at 12:16am.
A small mass M and a small mass 3M are 1.00 m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?

college physics  Aanu, Sunday, June 6, 2010 at 2:20am
do it this way
M(x)=3M(100x)
x=3003x
4x=300
x=75cm
or 0.75m

college physics  MathMate, Sunday, June 6, 2010 at 8:24am
Gravitational force
=GMm/r²
So for the mass m between masses M and 3M, one metre apart, equate the gravitational forces:
GMm/x² = G(3M)m/(1x)²
Solve for x.
[(√31)/2]
Answer This Question
Related Questions
 physics  a small mass M and a small mass 3M are 1.00 m apart. where should you ...
 physics  Three very small spheres are located along a straight line in space ...
 physics  Which of the following best describes the strength of the ...
 phy  Two objects attract each other gravitationally with a force of 3.5 1010 N...
 physics  A distance of 1 m separates two objects, one with a mass of 2 kg and ...
 Physics  I am really struggling with these 2 questions. Please help! 1)Mars has...
 Physics  Three very small spheres are located along a straight line in space ...
 Physics!!  The universal gravitational con stant is 6.672 × 10−11 N m2/...
 Physics  Given: The universal gravitational con stant is 6.672 × 10−11 N...
 Physics  Given: The universal gravitational con stant is 6.672 × 10−11 N...
More Related Questions