Posted by **Anonymous** on Sunday, June 6, 2010 at 12:16am.

A small mass M and a small mass 3M are 1.00 m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?

- college physics -
**Aanu**, Sunday, June 6, 2010 at 2:20am
do it this way

M(x)=3M(100-x)

x=300-3x

4x=300

x=75cm

or 0.75m

- college physics -
**MathMate**, Sunday, June 6, 2010 at 8:24am
Gravitational force

=GMm/r²

So for the mass m between masses M and 3M, one metre apart, equate the gravitational forces:

GMm/x² = G(3M)m/(1-x)²

Solve for x.

[(√3-1)/2]

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