Friday

August 29, 2014

August 29, 2014

Posted by **S Rey** on Saturday, June 5, 2010 at 2:28pm.

Options

A) The graph is a parabola with a minimum point.

B) The graph is a parabola with a maximum point.

C) The point (2, 2) lies on the graph.

D) The point (1, 6) lies on the graph.

E) The graph crosses the x-axis at x = −4and x =1.

F) The graph crosses the x-axis at x = −1and x =4.

G) The graph crosses the y-axis at y = −4.

- Math -
**Christiaan**, Saturday, June 5, 2010 at 9:19pmbecause the sign of the second degree term of the polynomial (x^2) is positive, its graph is a parabola with a minimum.

So A is true.

if you fill in -1 and 4 in the equation, you get 0, ergo the graph crosses the x-axis at -1 and 4. So F is true.

For x = 0, y= -4, so the graph crosses the y-axis at -4, so G is also true.

**Related Questions**

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

maths - Choose the THREE options that define sequences that do not converge. ...

math - Which three options are true about the quadratic equation?? y= 4t^2 + 16t...

maths - Which three options are true about the quadratic equation?? y= 4t^2 + ...

College Algebra - Find the equation of the parabola y = ax2 + bx + c that passes...