Posted by **Anonymous** on Saturday, June 5, 2010 at 1:00pm.

during the first part of a trip a canoeist travels 64 miles at a certain speed. the canoeist travels 11 miles on the second part of the trip at a 5 mph slower. the total time for the trip is 2 hrs. what speed on each part of the trip

- algebra -
**Terry**, Saturday, June 5, 2010 at 2:03pm
Given:

d1 = 64

d2 = 11

t(total) = 2

s1 = ?

s1 = s2 + 5

Ask yourself, what t really is?

t(total) = d1/s1 + d2/s2

substituting s1 as s2 + 5:

2 = 64/(s2+5) + 11/(s2)

Common denominator: multiply s(s+5)/s(s+5)and you eventually get:

2s^2 - 65s - 55 = 0

Same old quadratic formula:

s2 = 33.325 mph

s1 = s2 + 5 = 38.325 mph

Plug the # back in the original equation... 2 = 2, checked!

## Answer This Question

## Related Questions

- Algebra - During the first part of a trip, a canoeist travels 98 miles at a ...
- algebra 2 - During the first part of a trip a canoeist travels 26 miles at a ...
- algebra - Can someoe please help me figure this out? During the first part of a ...
- algebra - During the first part of a trip, a canoeist travels 69 miles at a ...
- ALGEBRA - DURING THE FIRST PART OF A TRIP, A CANOEIST TRAVELS 35 MILES AT A ...
- Algebra - During the first part of a trip, a canoeist travels 57 miles at a ...
- algebra - During the first part of a trip, a canoeist travels 69 miles at a ...
- MAT117 - During the first part of a trip, a canoeist travels 68 miles at a ...
- Math - During the first part of a trip, a canoeist travels 33 miles at a certain...
- Algebra - During the first part of a trip, a canoeist travels 28 miles at...

More Related Questions