Posted by **Anonymous** on Saturday, June 5, 2010 at 1:00pm.

during the first part of a trip a canoeist travels 64 miles at a certain speed. the canoeist travels 11 miles on the second part of the trip at a 5 mph slower. the total time for the trip is 2 hrs. what speed on each part of the trip

- algebra -
**Terry**, Saturday, June 5, 2010 at 2:03pm
Given:

d1 = 64

d2 = 11

t(total) = 2

s1 = ?

s1 = s2 + 5

Ask yourself, what t really is?

t(total) = d1/s1 + d2/s2

substituting s1 as s2 + 5:

2 = 64/(s2+5) + 11/(s2)

Common denominator: multiply s(s+5)/s(s+5)and you eventually get:

2s^2 - 65s - 55 = 0

Same old quadratic formula:

s2 = 33.325 mph

s1 = s2 + 5 = 38.325 mph

Plug the # back in the original equation... 2 = 2, checked!

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