Posted by Lucinda on Friday, June 4, 2010 at 9:32pm.
I GOT THIS WRONG IN AN ASSIGNMENT. I HAVE AN EXAM IN 2 DAYS. CAN YOU SHOW ME HOW TO DO IT PLS.
What is the pH of a 2.62 x 10 1 M NaNO2 solution ? NB the pKa for HNO2 = 3.153.
12.13
13.42
1.87
8.29
0.58

CHEMISTRY> HELP QUICK! pls  DrBob222, Saturday, June 5, 2010 at 12:21am
NaNO2 is the salt of a strong base (NaOH) and a weak acid (HNO2). The NO2^ is hydrolyzed.
NO2^ + HOH ==> HNO2 + OH^
Kb = (Kw/Ka) = (HNO2)(OH^)/(NO2^)
Set up an ICE chart.
You know Kw. You can calculate Ka from pKa. (HNO2) will be x. (OH^) will be x. (NO2^) = 0.262. Solve for x, convert to pOH, then to pH. I found pH = 8.285 which I would round to 8.28 but I would pick the 8.29 for the answer.
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