Posted by **Lucinda** on Friday, June 4, 2010 at 9:32pm.

I GOT THIS WRONG IN AN ASSIGNMENT. I HAVE AN EXAM IN 2 DAYS. CAN YOU SHOW ME HOW TO DO IT PLS.

What is the pH of a 2.62 x 10 -1 M NaNO2 solution ? NB the pKa for HNO2 = 3.153.

12.13

13.42

1.87

8.29

0.58

- CHEMISTRY> HELP QUICK! pls -
**DrBob222**, Saturday, June 5, 2010 at 12:21am
NaNO2 is the salt of a strong base (NaOH) and a weak acid (HNO2). The NO2^- is hydrolyzed.

NO2^- + HOH ==> HNO2 + OH^-

Kb = (Kw/Ka) = (HNO2)(OH^-)/(NO2^-)

Set up an ICE chart.

You know Kw. You can calculate Ka from pKa. (HNO2) will be x. (OH^-) will be x. (NO2^-) = 0.262. Solve for x, convert to pOH, then to pH. I found pH = 8.285 which I would round to 8.28 but I would pick the 8.29 for the answer.

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