Posted by :) on .
find algebraically the equation of the axis of symmetry and the coordinates of the vertex of the parabola whose equation is y=-2x^2-8x+3. explain the steps please. :)
The axis of symmetry of a parabola of the form y=ax²+bx+c is always vertical.
If a > 0, the parabola is concave upwards, and if a<0, the parabola is concave downwards.
The vertex of a parabola can be obtained by completing the squares, namely
x= -b/2a, at which point
Thus the vertex of the parabola
y=ax²+bx+c is at
The vertical axis of symmetry passes through the vertex, thus has the equation:
Apply the above the equation to the given problem and post the answer for verification if required.