Wednesday

January 28, 2015

January 28, 2015

Posted by **:)** on Friday, June 4, 2010 at 9:12pm.

- algebra -
**MathMate**, Friday, June 4, 2010 at 9:56pmThe axis of symmetry of a parabola of the form y=ax²+bx+c is always vertical.

If a > 0, the parabola is concave upwards, and if a<0, the parabola is concave downwards.

The vertex of a parabola can be obtained by completing the squares, namely

y=a((x+(b/2a)²+c/a-(b/2a)²)

or at

x= -b/2a, at which point

y=c-b²/4a

Thus the vertex of the parabola

y=ax²+bx+c is at

(-b/2a, c-b²/4a)

The vertical axis of symmetry passes through the vertex, thus has the equation:

x=-b/2a

Apply the above the equation to the given problem and post the answer for verification if required.

**Answer this Question**

**Related Questions**

algebra - Find algebraically the equation of the axis of symmetry and the ...

math - 1 identify the coordinates of the vertex and the equation of the axis of ...

ALG. REPOST TYPO - Find the coordinates of the vertex and the equation of the ...

ALG. - Find the coordinates of the vertex and the equation of the axis of ...

ALG - Find the coordinates of the vertex and the equation of the axis of ...

GRAPHING HELP - Find the coordinates of the vertex and the equation of the axis ...

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

alg. - Find the coordinates of the vertex and the equation of the axis of ...

Pre Cal. - 1. Identify the conic section represented by: 9y^2+4x^2 - 108y+24x= -...

Algebra - Tell whether the graph opens up or down. Find the coordinates of the ...