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In the summer of 2008 the population of cuckoos in an area was estimated as 560 pairs. If the numbers returning are declining at 4% each year, calculate
(a) the number of pairs of cuckoos in the area in the summer of 2009;
(b) the number of pairs of cuckoos in the area in the summer of 2020

  • Math - ,

    so my guess is that you would start with what ya got
    2008 560-4%
    2009 559.96-4%
    2010 559.92-4%
    (continue til you get to 2020)
    sooo;
    a.) 559.92
    b.) 559.52

  • Math - ,

    If the population declines at 4%, it means that the surviving population is 96% of the previous year.

    In the summer of 2008, there were 560 pairs. So in the summer of 2009, there were 560*(96/100)
    = 537.6 pairs (theoretically)
    = 538 pairs

    In the summer of 2009, the population declined again to 96% of the theoretical population of 2008, thus
    537.6*(96/100)
    =516.1 pairs (theoretically)
    = 516 pairs (rounded)

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