1 OVER T MINUS 2 EQUALS T OVER 8 PLEASE HELP ME SOLVE
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Sra
maybe you mean
1/(t-2) = t/8
8 = t^2 - 2 t
t^2 -2 t -8 = 0
(t-4)(t+2) = 0
t = 4 or t = -2
To solve the equation 1/t - 2 = t/8, we need to isolate the variable t.
1. Start by adding 2 to both sides of the equation:
1/t - 2 + 2 = t/8 + 2
1/t = t/8 + 2
2. Next, simplify the right side of the equation by finding a common denominator for t/8 + 2:
1/t = (t + 16)/8
3. Multiply both sides of the equation by t to eliminate the fraction on the left side:
t * (1/t) = t * (t + 16)/8
1 = (t^2 + 16t)/8
4. Distribute t on the right side:
1 = (t^2 + 16t)/8
1 = t^2/8 + 16t/8
5. Multiply both sides of the equation by 8 to eliminate the fraction:
8 * 1 = 8 * (t^2/8 + 16t/8)
8 = t^2 + 16t
6. Rearrange the equation in the standard quadratic form, t^2 + 16t - 8 = 0.
At this point, we have a quadratic equation. To solve it, you can use the quadratic formula or factorization. If you use the quadratic formula, which is given by t = (-b ± √(b^2 - 4ac)) / 2a, you can substitute the values a = 1, b = 16, and c = -8 into the formula. Then, simplify to find the values of t.