Saturday

February 28, 2015

February 28, 2015

Posted by **Jasmin** on Thursday, June 3, 2010 at 10:08pm.

1) 1

2) 2

3) 3

4) 0

- 11th grade -
**MathMate**, Thursday, June 3, 2010 at 10:40pmAngle A=45, AB=10, and BC=8.

This is an SSA configuration which*could*result in 0, 1 or two distinct triangles, depending on the length of the "dangling" leg BC, i.e. the side which does not touch the given angle A.

To determine which case applies, we construct a triangle where the side BC' cuts AC' at C' and make a right angle with AC'. Calculate the length BC'.

In this case angle C=90°, therefore angle B=45°. From an isosceles triangle with AB as the hypotenuse, BC'=5√2=7.071

Since BC=8 is greater than BC', there are two distinct triangles where the two possible positions of C are on each side of C'.

If

- 11th grade -
**Foggy**, Wednesday, February 26, 2014 at 8:53pmGggyy

**Answer this Question**

**Related Questions**

Math - Find he number of distinct triangles with integer sides and perimeter 10 ...

11th grade - I'm doing The Ambiguos case of triangles given SSA. My givens are a...

11th grade - what are some greatest weeknesses of caesar rodney?

11th grade - The students of litchfield High school are in grades 9,10,11,12. Of...

11th grade-Calculas - The number of hours of daylight D depends upon the ...

11th grade Algebra - A number is multiplied by -3 and then this product is ...

11th grade - determine the number of significant figures in each following ...

Math - The hypotenuse of,c of right triangle ABC is 7.0 m long. A trigonometric ...

11th grade math algebra 2 trig - the tens digit of a two digit number is 6 more ...

11th grade Algebra II - if the roots of ax^2+bx+c=0 are real, rational, and ...