How much heat is needed to raise 300g of Ethanol from 0 C to 20 C?
q = mass ethanol + specific heat ethanol x delta T.
14.6 KJ
To calculate the amount of heat needed to raise the temperature of a substance, you can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q is the amount of heat required (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
For Ethanol, the specific heat capacity is approximately 2.44 J/g°C. Therefore, we can substitute the given values into the formula:
m = 300 g
c = 2.44 J/g°C
ΔT = 20°C - 0°C = 20°C
Q = 300 g * 2.44 J/g°C * 20°C
Q = 14,640 Joules
Therefore, to raise 300 grams of Ethanol from 0°C to 20°C, approximately 14,640 Joules of heat energy is needed.