Posted by Jeff on Thursday, June 3, 2010 at 6:42pm.
I am assuming that you mean that the hunters gun and the center of the bullseye of the target are the same distance from the ground.
Considering the horizontal velocity of the bullet alone, it will reach the target in 125/227 = .55 sec.
In this .55 sec., gravity will pull the trajectory of the bullet down a distance of h = gt^2/2 = 9.8(.55)^2/2 = 1.48m, thereby missing the center of the bullseye by 1.48m. A realistic diameter of the bullseye would alter this result.
If the target were something like a ping-pong ball, the miss distance of 1.48m becomes more realistic.
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