On a 120 km track, a train travels the first 30 km at a uniform speed of 30km/h. How fast must the train travel the next 90 km so as to average 60km\h for the entire trip?
Let the train must travel with a speed of x km .
Average speed = Total distance travelled\Total time taken
60km\hr =30 km + 90km\x + 1hr
x +1hr =120km \60
x = 2 - 1
= 1
time taken to cover 90km = 90\1
=90km\hr
ans - The train must travel the next 90 km with a speed of 90 km/h so that the average speed is 60 km/h.
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The train must travel the next 90 km / hr . So that the average speed is 60 km / hr
90km/hr
A train travels the first 30 kilometre of 120 kilometre track with a uniform speed of 30 kilometre per hour what should be the speed to cover the remaining distance of the track so that its average speed is 60 kilometre for the entire trip
Pls give me answer
90km/he
Speed of train in first 30 km
V1=30km/h
Speed of the train in the next 90 km , v2
Average speed = 60 km/ h=( V1+v2)/ 2
V2=90 km / hr