Posted by **masood** on Thursday, June 3, 2010 at 2:22am.

A random sample of size 20 from a normal population will sample mean 42 and sample standard deviation of 6 . To test the hypothesis the population mean 44 at 5% level of significance , find the p-value and comment

- statistics -
**PsyDAG**, Thursday, June 3, 2010 at 10:49am
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√(n-1)

Since only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

## Answer This Question

## Related Questions

- Statistics - A random sample of size 20 from a normal population will sample ...
- statistics - Given a sample size of 38, with sample mean 660.3 and sample ...
- Statistics - Kind attention Psydag: A random sample of size 20 from a normal ...
- statistics - In performing a hypothesis test, the null hypothesis is population...
- statistics - A sample of 40 observations is selected from one approximately ...
- statistics - A sample of 40 observations is selected from one approximately ...
- Statistics - This is the first question..... For a population that has a ...
- Statistic - A random sample of size 20 drawn from a normal distribution has a ...
- Statistics - I have a question that involves explaining what is wrong in each of...
- statistics - For each of the following samples that were given an experimental ...

More Related Questions