how do you solve 5z-43=2z+80
minus 2z on both sides
3z-43=80
then add 43 to each side
3z=123
then divide 123 by 3 and you get
z=41
5z-43=2z+80
5z - 2z = 80 + 43
3z = 123
z = ?
To solve the equation 5z - 43 = 2z + 80, you can follow these steps:
1. Start by simplifying both sides of the equation. Combine like terms by moving the constants to one side and the variable terms to the other side. You can do this by performing the inverse operation of adding or subtracting.
5z - 43 + 43 = 2z + 80 + 43
5z = 2z + 123
2. Next, isolate the variable term (2z) on one side of the equation. You can do this by performing the inverse operation of subtracting or adding.
5z - 2z = 2z - 2z + 123
3z = 123
3. Finally, solve for z by dividing both sides of the equation by the coefficient of z, which is 3.
3z/3 = 123/3
z = 41
So the solution to the equation 5z - 43 = 2z + 80 is z = 41.