Calculate the pH and pOH of a solution prepared by dissolving 0.93 g of HCl in enough water to give 0.40 L of solution.

I figured it out! Thanks!

Can u show your working pls?

To calculate the pH and pOH of a solution, we need to use the concentration of H+ ions or OH- ions in the solution. In this case, we are given the mass of HCl and the volume of the solution.

Step 1: Convert the mass of HCl to moles.
The molar mass of HCl is 36.46 g/mol. To convert the mass to moles, we use the formula:

moles = mass / molar mass
moles = 0.93 g / 36.46 g/mol
moles ≈ 0.0255 mol HCl

Step 2: Calculate the concentration of HCl.
The concentration is given by:

concentration = moles / volume
concentration = 0.0255 mol / 0.40 L
concentration = 0.0638 M HCl

Step 3: Calculate the concentration of H+ ions.
Since HCl is a strong acid, it dissociates completely in water, forming H+ ions and Cl- ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl:

[H+] = 0.0638 M

Step 4: Calculate the pH.
The pH is a measure of the concentration of H+ ions in a solution and is given by the formula:

pH = - log[H+]
pH = - log(0.0638)
pH ≈ 1.195

Step 5: Calculate the pOH.
The pOH is a measure of the concentration of OH- ions in a solution and is given by the formula:

pOH = - log[OH-]

Since HCl is a strong acid, it reacts with water to form H3O+ ions, and the concentration of OH- ions is negligible. Therefore, we can assume that the concentration of OH- ions is very low.

Thus, the pOH can be considered as 0.

Therefore, the pH of the solution is approximately 1.195, and the pOH is 0.