how do you solve the equation
15x^2-9x=12x^2+28x
Subract 12x^2 from both sides first. This gives you 3x^2-9x=28x
Now subtract 28x from both sides. This gives you 3x^2-37x=0
Now factor out 3x. This will give you 3x(x-37/3)=0
Therefore, x=0,37/3
I hope that helps!