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April 29, 2016
Posted by **Ashley J** on Tuesday, June 1, 2010 at 10:06pm.

8y(y^2-27)

x^2+36=

(x+6)(x+6)

Facatoring completely

are they right. corrected if wrong

- algebra -
**Reiny**, Tuesday, June 1, 2010 at 10:13pmThe first one is the difference of cubes

a^3 - b^3 = (a-b)(a^2 + ab + b^2)

so

8y^3 - 27

= (2y-3)(4y^2 + 6y + 9)

the second doesn't factor over the real numbers.