Posted by Darren on Tuesday, June 1, 2010 at 8:28pm.
first one:
add all 3 equations --> 2x + y = -4
now add this to the second ...
3x = -3
x = -1
sub that onto the second and third to get y and z
"play around" with the second question in a similar way.
I would use substitution,
e.g. for the first ---> y = 2x
from the second z = 2y - 7
z = 2(2x) - 7
= 4x - 7
now in the third
2z - x = 0
2(4x-7) - x = 0
7x = 14
x = 2
Now you can find the other two.
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