Posted by **johnny** on Tuesday, June 1, 2010 at 7:56pm.

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 58.8m/s^2 . The acceleration period lasts for time 8.00s until the fuel is exhausted. After that, the rocket is in free fall.

Find the maximum height y_max reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.8m/s^2

Im not sure what equations i should use to get started

- Physics -
**tchrwill**, Wednesday, June 2, 2010 at 2:26pm
The general equations of accelerated motion also apply to falling (or rising) bodies with the exception that the term "a" for acceleration is replaced by the term "g” for the acceleration due to gravity). This results in

....Vf = Vo + gt (the term “g” for acceleration due to gravity is assumed constant)

....d = Vo(t) + g(t^2)/2

....Vf^2 = Vo^2 + 2gd

As written, these expressions apply to falling bodies. The equations that apply to rising bodies are

.....Vf = Vo - gt (the term “g” for acceleration due to gravity is assumed constant)

.....d = Vo(t) - g(t^2)/2

.....Vf^2 = Vo^2 - 2gd

All of the above ignores surface friction.

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