Posted by Bianca on Tuesday, June 1, 2010 at 2:10am.
Assuming that both observers are at an elevation level with the base of the building.
Height of the building, H = 120m
Distance of observer 1 = D1
Angle of elevation = α
By the definition of tangent = opp/adj
H/D1=tan(α), therefore
D1=H/tan(α)
Since H and α are known, D1 can be calculated numerically.
Distance of observer 2 = D2
Angle of elevation = β
H/D2=tan(β)
D2=H/tan(β)
Distance between observers = D2-D1
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