Wednesday

July 30, 2014

July 30, 2014

Posted by **Katy** on Monday, May 31, 2010 at 7:43pm.

I'm stuck on this problem because I'm getting thrown off on how to factor this. Here's my work so far:

-{[(dy/dx)y + y]sin xy} = 4x - 3(dy/dx)

-{[(dy/dx)y + y]sinxy} + 3(dy/dx) = 4x

...now what?

Thx

- Calculus (repost) -
**Damon**, Monday, May 31, 2010 at 9:12pmfactor out dy/dx which is what you want

dy/dx [ 3 -y sinxy] = [ 4 x + y sin xy ]

so

dy/dx =[ 4 x + y sin xy ] / [ 3 -y sinxy]

- Calculus (repost) -
**MathMate**, Monday, May 31, 2010 at 9:29pmThere is a minor correction to the original differentiation:

-{[(dy/dx)**x**+ y]sin xy} = 4x - 3(dy/dx)

**Related Questions**

Calculus - Use implicit differentiation to find dy/dx if cos xy = 2x^2 - 3y. I'm...

Calculus - How do you use imlicit differentiation to differentiate e^(xy)? I ...

Implicit differentiation calculus - PLEASE HELP , I DON'T UNDERSTAND find dy/dx ...

Calculus - Use implicit differentiation to find dy/dx. e^4x = sin(x+2y). This is...

Calculus 1 Implicit differentiation - Help please help me understand what i am ...

Math - Calculus Question. - hey can someone explain to me the relationship ...

Calculus 1 - implicit differentiation - I do not understand implicit ...

Calculus 1 - implicit differentiation - I do not understand implicit ...

Calculus: implicit differentiation - Find dy/dx by implicit differentiation 1. x...

calculus - Given y^4 -x^4=16 find and simplify d2y/dx2 using implicit ...