Posted by Katy on Monday, May 31, 2010 at 7:43pm.
Use implicit differentiation to find dy/dx if cos xy = 2x^2  3y.
I'm stuck on this problem because I'm getting thrown off on how to factor this. Here's my work so far:
{[(dy/dx)y + y]sin xy} = 4x  3(dy/dx)
{[(dy/dx)y + y]sinxy} + 3(dy/dx) = 4x
...now what?
Thx

Calculus (repost)  Damon, Monday, May 31, 2010 at 9:12pm
factor out dy/dx which is what you want
dy/dx [ 3 y sinxy] = [ 4 x + y sin xy ]
so
dy/dx =[ 4 x + y sin xy ] / [ 3 y sinxy]

Calculus (repost)  MathMate, Monday, May 31, 2010 at 9:29pm
There is a minor correction to the original differentiation:
{[(dy/dx)x + y]sin xy} = 4x  3(dy/dx)
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