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August 27, 2014

August 27, 2014

Posted by **Vince** on Monday, May 31, 2010 at 2:47pm.

- Math -
**MathMate**, Monday, May 31, 2010 at 8:50pmLet P=peter's age, and

M=Mary's age.

M=(2/3)P.... (1)

Two years ago, Mary's age was M-2, and it was what Peter's age*will*be in 5 years time (P+5)/2

Therefore

M-2 = (P+5)/2

Substitute M from (1)

(2/3)P-2 = (P+5)/2

Solve for P to get P=27, and M=18

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