Wednesday
March 29, 2017

Post a New Question

Posted by on .

A basketball is shot from 2 meters up at an angle of 60° above the x axis at an initial velocity of 9 m/s.What is the maximum height the ball will reach?

  • physics - ,

    initial distance up = 2
    initial velocity component up = 9 sin 60 = 7.79
    v = 9 sin 60 - 9.8 t
    when v = 0, we are there
    9.8 t = 7.79
    t = .795 seconds to top
    h = 2 + 7.79(.795) - 4.9(.795^2)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question