How many molecules of hydrogen are produced if 13.05 g of Zn reacts with excess hydrochloric acid equation Zn plus HCL equals ZnCl2 plus H2?
Two
To find the number of molecules of hydrogen produced, you need to follow these steps:
Step 1: Convert the given mass of zinc (Zn) to moles.
The molar mass of zinc is 65.38 g/mol. Therefore, divide the given mass (13.05 g) by the molar mass to get the number of moles of Zn:
13.05 g Zn × (1 mol Zn / 65.38 g Zn) = 0.1995 mol Zn
Step 2: Determine the stoichiometry between Zn and H2.
Looking at the balanced equation, you can see that 1 mol of zinc (Zn) reacts with 1 mol of hydrogen (H2). Therefore, the number of moles of H2 produced will be the same as the number of moles of zinc consumed.
Step 3: Calculate the number of molecules using Avogadro's number.
Avogadro's number states that 1 mole of a substance contains 6.022 × 10^23 entities (atoms, molecules, or ions). Therefore, multiply the number of moles of H2 by Avogadro's number to find the number of molecules:
0.1995 mol H2 × (6.022 × 10^23 molecules H2 / 1 mol H2) = 1.199 × 10^23 molecules H2
So, approximately 1.199 × 10^23 molecules of hydrogen will be produced when 13.05 g of Zn reacts with excess hydrochloric acid.