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July 25, 2014

July 25, 2014

Posted by **Laplace transform** on Monday, May 31, 2010 at 6:59am.

- Math, not "college" -
**Writeacher**, Monday, May 31, 2010 at 7:30amPlease type your

__subject__in the**School Subject**box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.

- Integral calculus -
**MathMate**, Monday, May 31, 2010 at 10:18amWhen the sin/cos are in odd powers, use the substitution

cosθdθ=d(sinθ), or

sinθdθ=-d(cosθ)

∫sin³θcos³θd&theta (from 0 to π/2)

=∫sin³θ(1-sin²θ) (cosθdθ)

=∫(sin³θ-sin^{5}θ)(d(sinθ)) (from 0 to sin(π/2))

=[sin^{4}θ/4-sin^{6}θ/6](from 0 to 1)

=1/12

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