Posted by Miranda on Sunday, May 30, 2010 at 10:35pm.
Since i=sqrt(-1), we can suggest
i=(-1)^(1/2) in exponent form.
Also, since
e^(ix)=cos(x) + i*sin(x)
we put x=π/2 to get
e^(iπ/2)
= cos(π/2) + i*sin(π/2)
= 0 + i*1
=i
However, i is also on the left-hand expression, so it is probably not the answer sought after.
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