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April 19, 2014

April 19, 2014

Posted by **Miranda** on Sunday, May 30, 2010 at 10:35pm.

i

i is the complex number.

- calculus -
**MathMate**, Sunday, May 30, 2010 at 10:47pmSince i=sqrt(-1), we can suggest

i=(-1)^(1/2) in exponent form.

Also, since

e^(ix)=cos(x) + i*sin(x)

we put x=π/2 to get

e^(iπ/2)

= cos(π/2) + i*sin(π/2)

= 0 + i*1

=i

However, i is also on the left-hand expression, so it is probably not the answer sought after.

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