Friday

January 30, 2015

January 30, 2015

Posted by **Adam** on Saturday, May 29, 2010 at 8:34pm.

- CALC -
**MathMate**, Saturday, May 29, 2010 at 10:09pmArea to be fenced in, A = 1,500,000 sq.ft.

Width (shorter side) = x

Length (longer side) = A/x

Total length of fence, L

= 3x+2(A/x)

Differentiate with respect to x:

dL/dx = 3 - 2A/x²

To get minimum length,

dL/dx = 0

3 - 2A/x² = 0

x=sqrt(2A/3)=1000 ft.

Check that d²L/dx²>0 for L to be a minimum.

Calculate the length of fence required.

- CALC -
**Adam**, Sunday, May 30, 2010 at 1:21amthank you so much for the clear explanation. i really understand how to do the problem now! i appreciate it!

- CALC :) -
**MathMate**, Sunday, May 30, 2010 at 8:34amYou're welcome!

- CALC -
**Kamsan**, Saturday, November 12, 2011 at 9:17pmwhat is the answer of this question?

**Answer this Question**

**Related Questions**

Calc - A rancher wants to fence in an area of 1500000 square feet in a ...

Calculus - A rancher wants to fence in an area of 500000 square feet in a ...

Calculus - A rancher wants to fence in an area of 5189400 square feet in a ...

math - I've tried this many times, but I keep getting a really big answer. A ...

calculus - A rancher wants to fence in an area of 3000000 square feet in a ...

Calculus-Applied Optimization Quiz Problem - A rancher wants to fence in a ...

area and perimeter - a farmer wishes to build a fence around a rectangular field...

math - A rectangular field is to be enclosed by a fence. Two fences parallel to ...

Calculus - A rancher wants to make an animal pen by fencing in an area of ...

calc - A farmer intends to fence o a rectangular pen for his pig Wilbur, using ...