Posted by **Sheryl** on Saturday, May 29, 2010 at 1:27am.

How do you factor this completely:

x^3 + ax + 3a + 3x^2

- Math 209-College Mathematics II -
**drwls**, Saturday, May 29, 2010 at 2:17am
You are in luck with this one. Two pairs of terms have x + 3 as a common factor.

x^3 + ax + 3a + 3x^2

= x^2(x + 3)+ a(x + 3)

= (x^2 + a)(x + 3)

= (x + ia)(x - ia)(x + 3)

(i is the square root of -1)

Two of the three roots are complex, for real a.

- Math 209-College Mathematics II -
**Anonymous**, Saturday, May 29, 2010 at 2:20pm
X^3+ax+3a+3x^2

x^2+3x^2+ax+3a

x(x+3)+a(x+3)

(x+a)(x+3)

x= -a, x= -3

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