Posted by Sheryl on Saturday, May 29, 2010 at 1:27am.
How do you factor this completely:
x^3 + ax + 3a + 3x^2

Math 209College Mathematics II  drwls, Saturday, May 29, 2010 at 2:17am
You are in luck with this one. Two pairs of terms have x + 3 as a common factor.
x^3 + ax + 3a + 3x^2
= x^2(x + 3)+ a(x + 3)
= (x^2 + a)(x + 3)
= (x + ia)(x  ia)(x + 3)
(i is the square root of 1)
Two of the three roots are complex, for real a.

Math 209College Mathematics II  Anonymous, Saturday, May 29, 2010 at 2:20pm
X^3+ax+3a+3x^2
x^2+3x^2+ax+3a
x(x+3)+a(x+3)
(x+a)(x+3)
x= a, x= 3
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