Posted by Amber on Friday, May 28, 2010 at 10:11pm.
Here some facts about simple harmonic motion to help you answer these yourself.
(a) The angular frequency is w = 2 pi f radians per second.
Tha maximum velocity is w A, where a is the amplitude.
The spring constant k is related to w and M by
w = sqrt(k/m)
Compute w. You will need it later.
(b) 0.10 m is 2/3 of the maximum deflection. Potential energy is proportion do the square of deflection, and will be (2/3)^2 = 4/9 of the maximum energy, or
(4/9)*(1/2)*k*(Amplitude)^2. The velocity will be (5/9) of the maxiomum energy. Use that to solve for velocity.
(c) I already mentioned that the toal energy is (1/2)*k*(Amplitude)^2
(d) X = A cos wt
(a) 2,83ms (b) 2,11ms (c) 2,00j (d) x=acoswt .
Related Questions
Physics - A 0.70 kg mass at the end of a spring vibrates 4.0 times per second ...
Physics - A .6-kg mass at the end of a spring vibrates 3.0 times per second with...
physics - A 0.50 kg mass at the end of a spring vibrates 6.0 times per second ...
Physics - A spring force constant 210 N/m vibrates with an amplitude of 28.0 cm ...
physics - 1. a 2 kg body is attatched to a spring of negligible mass and ...
physics - A particle vibrates in Simple Harmonic Motion with amplitude. What ...
physics - a spring has a 2.000x10^3 N/m spring constant. how do you find the ...
Physics - A student gets a 2.9 kg mass to oscillate up and down on bottom of a ...
Physics - A particle of mass m = 0.40 kg oscillates on the end of a spring with ...
Physics 3 - A particle of mass m = 0.35 kg is oscillating on the end of a spring...
For Further Reading