If 24.7 of 0.250 M NaOH solution are needed to neutralize 19.8 mL of H2SO4 solution, what is the molarity of the H2SO4?
M*19.8*Heq=24.7*.250
Heq for sulfuric acid is 2
solve for M.
To find the molarity of the H2SO4 solution, we need to use the equation:
M1V1 = M2V2
Where:
M1 = Molarity of NaOH
V1 = Volume of NaOH (given as 24.7%)
M2 = Molarity of H2SO4 (what we want to find)
V2 = Volume of H2SO4 (given as 19.8 mL)
First, let's convert the given volume of NaOH from a percentage to a decimal:
V1 = 24.7% = 24.7/100 = 0.247
Now, we can substitute the given values into the equation:
(0.250 M) * (0.247) = M2 * (19.8 mL)
Simplifying the equation:
M2 = (0.250 M * 0.247) / 19.8 mL
M2 = 0.06175 M
Therefore, the molarity of the H2SO4 solution is 0.06175 M.
To find the molarity of the H2SO4 solution, we need to use the equation for neutralization between an acid and a base. The equation is:
acid + base -> salt + water
In this case, the acid is H2SO4, and the base is NaOH. The balanced equation for the neutralization reaction between H2SO4 and NaOH is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
Using the balanced equation, we can determine the mole ratio between H2SO4 and NaOH. The mole ratio is 1:2, meaning that for every 1 mole of H2SO4, we need 2 moles of NaOH.
First, let's calculate the number of moles of NaOH needed to neutralize the H2SO4:
moles of NaOH = volume of NaOH solution (in L) x molarity of NaOH
Given that 24.7% of a 0.250 M NaOH solution is needed, we can calculate the moles of NaOH:
moles of NaOH = 0.247 x (0.250 M NaOH) x (volume of NaOH solution in L)
Next, we use the mole ratio to determine the moles of H2SO4:
moles of H2SO4 = (1/2) x moles of NaOH
Now we can find the molarity of the H2SO4 solution:
molarity of H2SO4 = moles of H2SO4 / volume of H2SO4 solution (in L)
Given that 19.8 mL of H2SO4 solution is neutralized, we convert it to L:
volume of H2SO4 solution = 19.8 mL / 1000 mL/L = 0.0198 L
Finally, using the calculated values, we can find the molarity of the H2SO4 solution.