How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 degrees celcius

To determine the number of moles of oxygen, we can use the ideal gas law equation:

PV = nRT

Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)

First, let's convert the given temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 25°C + 273.15 = 298.15 K

Next, we can rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT

Substituting the given values:
P = 1.2 atm
V = 2.5 L
R = 0.0821 L·atm/(mol·K)
T = 298.15 K

n = (1.2 atm × 2.5 L) / (0.0821 L·atm/(mol·K) × 298.15 K)

Calculating,
n ≈ 0.124 mol

Therefore, approximately 0.124 moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 degrees Celsius.

To calculate the number of moles, you can use the Ideal Gas Law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given conditions to the correct units.

The given pressure is 1.2 atm, and the volume is 2.5 liters.

To convert the temperature from Celsius to Kelvin, you need to add 273.15 to the Celsius temperature. So, 25 degrees Celsius is equal to 25 + 273.15 = 298.15 Kelvin.

Now, we have all the values needed to apply the Ideal Gas Law equation:

PV = nRT

Substituting the values into the equation:

(1.2 atm) * (2.5 L) = n * (0.0821 L*atm/(mol*K)) * (298.15 K)

Simplifying the equation:

3 L*atm = n * 24.463 L*atm/(mol*K)

Dividing both sides of the equation by 24.463 L*atm/(mol*K):

n = (3 L*atm) / (24.463 L*atm/(mol*K))

n ≈ 0.1226 mol

Therefore, approximately 0.1226 moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25 degrees Celsius.

wryry

PV=nRT

n=PV/RT