In a fixed volume container, 6*10^23 molecules of a gas exert a pressure of 12 N/m^2. If 12*10^23 molecules of gas were added to the container, what would the pressure become?
P=pressure in atm
V=volume in L
T=absolute (kelvin) temperature
R=0.082 L atm/mole K
n=number of moles
***the answer is 36 N/m^2. I don't know how to get this answer. Thank you for the help!
Chemistry - Anonymous, Monday, May 19, 2014 at 2:15pm