How many moles of ammonium sulfate can be made from the reaction of 30.0
mol of NH3 with H2SO4 according to the following equation?
2NH3 � H2SO4 �¨ (NH4)2SO4
With excess sulfuric acid, you can make 15 mol ammonium sulfate.
How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?
To determine the number of moles of ammonium sulfate (NH4)2SO4 that can be formed from 30.0 mol of NH3, we need to use the balanced chemical equation given:
2NH3 + H2SO4 → (NH4)2SO4
From the equation, it is clear that the stoichiometric ratio between NH3 and (NH4)2SO4 is 2:1. This means that for every 2 moles of NH3, 1 mole of (NH4)2SO4 is formed.
So, to find the moles of (NH4)2SO4, we can use the stoichiometry in the following way:
30.0 mol NH3 × 1 mol (NH4)2SO4 / 2 mol NH3 = 15.0 mol (NH4)2SO4
Therefore, 15.0 moles of ammonium sulfate can be made from the reaction of 30.0 mol of NH3 with H2SO4.
To determine the number of moles of ammonium sulfate (NH4)2SO4 that can be produced from the reaction, we need to use the stoichiometry of the balanced chemical equation.
From the equation: 2NH3 + H2SO4 → (NH4)2SO4
It shows that for every 2 moles of NH3, we produce 1 mole of (NH4)2SO4.
Therefore, we can use the ratio of the coefficients to calculate the number of moles of (NH4)2SO4:
30.0 mol NH3 x (1 mol (NH4)2SO4 / 2 mol NH3) = 15.0 mol (NH4)2SO4
So, 15.0 moles of ammonium sulfate can be produced from the reaction of 30.0 moles of NH3 with H2SO4.