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Posted by on Thursday, May 27, 2010 at 10:16am.

How would I make z the subject of the formulae:

x=y(z-y)/z

  • Math - , Thursday, May 27, 2010 at 10:23am

    (z-y)/z = 1 - (y/z) = x/y
    y/z = 1 - (x/y)= (y-x)/y
    z/y = y/(y-x)
    z = y^2/(y-x)

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